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July 5th, 2017, 03:41 AM
#1
[RESOLVED] packaged task error - with thread & future
Hi
I'm following this youtube video while learning about packaged tasks and futures.
The code presented about two thirds of the way into the video, is as follows:
Code:
#include <future>
#include <iostream>
#include <deque>
int factorial(int N) {
int res = 1;
for (int i=N; i>1; i--) {
res *= i;
}
return res;
}
std::deque<std::packaged_task<int()> > task_q;
void thread_1() {
std::packaged_task<int()> t;
t = std::move(task_q.front());
t();
}
int main() {
std::thread t1(thread_1);
std::packaged_task<int()> t(std::bind(factorial, 6)); // "int" removed
std::future<int> fu = t.get_future();
task_q.push_back(t);
std::cout << fu.get() << std::endl;
t1.join();
return 0;
}
The idea behind the code is to take a packaged task and push into onto a queue, a running thread then pops the task and and executes the function object represented by the task.
A get() is then performed on the future (fu), associated with the packaged task (task_q), to obtain the result of the factorial.
But I get the following compile error:
Code:
g++ -Wall -o "thread18_example" "thread18_example.cpp" -L /usr/lib/x86_64-linux-gnu -lpthread -lboost_system (in directory: /home/C++/learn2_c++)
In file included from /usr/include/x86_64-linux-gnu/c++/6/bits/c++allocator.h:33:0,
from /usr/include/c++/6/bits/allocator.h:46,
from /usr/include/c++/6/string:41,
from /usr/include/c++/6/stdexcept:39,
from /usr/include/c++/6/array:39,
from /usr/include/c++/6/tuple:39,
from /usr/include/c++/6/functional:55,
from /usr/include/c++/6/future:38,
from thread18_example.cpp:1:
/usr/include/c++/6/ext/new_allocator.h: In instantiation of ‘void __gnu_cxx::new_allocator<_Tp>::construct(_Up*, _Args&& ...) [with _Up = std::packaged_task<int()>; _Args = {const std::packaged_task<int()>&}; _Tp = std::packaged_task<int()>]’:
/usr/include/c++/6/bits/alloc_traits.h:475:4: required from ‘static void std::allocator_traits<std::allocator<_CharT> >::construct(std::allocator_traits<std::allocator<_CharT> >::allocator_type&, _Up*, _Args&& ...) [with _Up = std::packaged_task<int()>; _Args = {const std::packaged_task<int()>&}; _Tp = std::packaged_task<int()>; std::allocator_traits<std::allocator<_CharT> >::allocator_type = std::allocator<std::packaged_task<int()> >]’
/usr/include/c++/6/bits/stl_deque.h:1522:30: required from ‘void std::deque<_Tp, _Alloc>::push_back(const value_type&) [with _Tp = std::packaged_task<int()>; _Alloc = std::allocator<std::packaged_task<int()> >; std::deque<_Tp, _Alloc>::value_type = std::packaged_task<int()>]’
thread18_example.cpp:27:21: required from here
/usr/include/c++/6/ext/new_allocator.h:120:4: error: use of deleted function ‘std::packaged_task<_Res(_ArgTypes ...)>::packaged_task(const std::packaged_task<_Res(_ArgTypes ...)>&) [with _Res = int; _ArgTypes = {}]’
{ ::new((void *)__p) _Up(std::forward<_Args>(__args)...); }
^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
In file included from thread18_example.cpp:1:0:
/usr/include/c++/6/future:1513:7: note: declared here
packaged_task(const packaged_task&) = delete;
^~~~~~~~~~~~~
Compilation failed.
Can anybody suggest why the error and a remedy?
Thanks
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July 5th, 2017, 04:40 AM
#2
Re: packaged task error - with thread & future
From the error messages,
Code:
packaged_task(const packaged_task&) = delete;
The problem is as above. The copy constructor for class packaged_task has been deleted so instances of class packaged_task can't be copied - they can only be moved.
All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!
C++23 Compiler: Microsoft VS2022 (17.6.5)
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July 5th, 2017, 05:02 AM
#3
Re: packaged task error - with thread & future
Thanks,
I've modified the code, to what is shown a bit later in the same video, to the following:
Code:
#include <future>
#include <iostream>
#include <deque>
int factorial(int N) {
int res = 1;
for (int i=N; i>1; i--) {
res *= i;
}
return res;
}
std::deque<std::packaged_task<int()> > task_q;
std::mutex mu;
std::condition_variable cond;
void thread_1() {
std::packaged_task<int()> t;
{
std::unique_lock<std::mutex> locker(mu); // use unique_lock, instead of lock_guard, because of condition_variable that blocks & unblocks
cond.wait(locker, []() { return !task_q.empty();}); // wait for task package to be available on queue
t = std::move(task_q.front()); // the move occurs, since t is not referenced in the main thread
task_q.pop_front();
}
t();
}
int main() {
std::thread t1(thread_1);
std::packaged_task<int()> t(std::bind(factorial, 5)); // "int" removed
std::future<int> fu = t.get_future();
{ // since queue is shared, use lock_guard
std::lock_guard<std::mutex> locker(mu);
task_q.push_back(std::move(t)); // perform move when placing onto queue
}
cond.notify_one();
std::cout << fu.get() << std::endl;
t1.join();
return 0;
}
The code works now, and moves the task, as you suggested. In addition, since the queue is shared, a lock_guard and unique_lock is introduced to protect the pushing & popping.
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