use of algorithms in function cause ERROR: no instance of overloaded function

[2kaud]

Do you mean something like:

#include <iostream>
#include <algorithm>

constexpr size_t ELEMENTS { 8 };
constexpr size_t SLOTS { 32 };

void show(const int(&arr)[ELEMENTS]) {
	for (const auto& c : arr)
		std::cout << c;

	std::cout << '\n';
}

void bool_element_option_03(const int(&arr_value)[ELEMENTS], int(&arr_copy_value)[ELEMENTS], int(&arr_elements)[ELEMENTS][SLOTS]) {
	std::copy(std::begin(arr_value), std::end(arr_value), std::begin(arr_copy_value));
	std::sort(std::rbegin(arr_copy_value), std::rend(arr_copy_value));

	for (const auto& e : arr_elements)
		for (const auto& v : e)
			std::cout << v << ' ';

	std::cout << '\n';

	std::cout << "\nReverse sorted:\n";
	show(arr_copy_value);
}

int main() {
	const int arr_value[ELEMENTS] { 1, 2, 9, 4, 5, 6, 7, 8 };
	int arr_copy_value[ELEMENTS] {};
	int arr_elements[ELEMENTS][SLOTS] {};

	std::cout << "\nOriginal order:\n";
	show(arr_value);
	bool_element_option_03(arr_value, arr_copy_value, arr_elements);
}