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September 17th, 2002, 03:15 AM
#1
How To Use Search (Template) in algorithms??
Any body knows how is search template to be used which is declaed in algorithms??
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September 17th, 2002, 07:52 AM
#2
Here is a simple example. Maybe if you give a brief
description of your problem, more info can be provided.
(might use find() instead of search(), etc.)
Code:
#include <iostream>
#include <list>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
list<int> mylist;
mylist.push_back(1);
mylist.push_back(4);
mylist.push_back(2);
mylist.push_back(5);
mylist.push_back(7);
vector<int> myvector;
myvector.push_back(2);
myvector.push_back(5);
//
// check if "myvector" is in "mylist"
//
list<int>::iterator pos;
pos = search(mylist.begin(),mylist.end(),myvector.begin(),myvector.end());
//
//
if (pos != mylist.end())
{
cout << "myvector found in mylist starting with element ";
cout << distance(mylist.begin(),pos) + 1 << endl; // maybe not use "+1" ?
}
else
{
cout << "myvector not found in mylist" << endl;
}
return 0;
}
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September 17th, 2002, 10:08 PM
#3
Thanx and more!
Thanks a lot buddy,
The problem was that i read the MSDN which explained in the following way
search
template<class FwdIt1, class FwdIt2>
FwdIt1 search(FwdIt1 first1, FwdIt1 last1,
FwdIt2 first2, FwdIt2 last2);
template<class FwdIt1, class FwdIt2, class Pred>
FwdIt1 search(FwdIt1 first1, FwdIt1 last1,
FwdIt2 first2, FwdIt2 last2, Pred pr);
The first template function determines the lowest value of N in the range [0, (last1 - first1) - (last2 - first2)) such that for each M in the range [0, last2 - first2), the predicate *(first1 + N + M) == *(first2 + M) is true. It then returns first1 + N. If no such value exists, the function returns last1. It evaluates the predicate (last2 - first2) * (last1 - first1) times, at most.
The second template function behaves the same, except that the predicate is pr(*(first1 + N + M), *(first2 + M)).
My problem was to comprehend the above language. I would still like to understand it (if someone help me out). The very first thing is 'predicate' which is not understood.
Thanx buddy.
Neerad
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September 18th, 2002, 04:17 AM
#4
A predicate is simply a function (or function object) that returns a bool. So, the following are predicates:
Code:
bool less(int i, int j)
{
return i < j;
}
class UnaryPredicate
{
public:
UnaryPredicate(int val) : value_(val) {}
bool operator()(int i)
{
return i == value_;
}
private:
int value;
};
A binary predicate takes two arguments, and a unary predicate takes one argument. The STL defines lots of predicates for you: less<>, greater<>, not<> and so on.
The MSDN descriptions of the algorithms are particularly awful. I would suggest that you invest in a good STL book (Josuttis or Austern are both worth reading) if you're going to be using STL in any great amount.
Correct is better than fast. Simple is better than complex. Clear is better than cute. Safe is better than insecure.
-- Sutter and Alexandrescu, C++ Coding Standards
Programs must be written for people to read, and only incidentally for machines to execute.
-- Harold Abelson and Gerald Jay Sussman
The cheapest, fastest and most reliable components of a computer system are those that aren't there.
-- Gordon Bell
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September 20th, 2002, 09:57 PM
#5
Thanx
Thanx buddy,
This methametics will some day kill me. I gotta start doing some maths again right from grade 5 onwards!
Thanx a lot.
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