new and delete with multi_dimension array

[JamesSchumacher]

#include <windows.h>
#include <iostream>
#include <stdlib.h>
#include <time.h>

int main(int _argc,char * _argv[]) throw()
{
	srand(::GetTickCount());
	int *** pPointerToPointerOfPointers = new int **[10];
	for (int i = 0; i < 10; ++i)
	{
		pPointerToPointerOfPointers[i] = new int *[10];
		for (int x = 0; x < 10; ++x)
		{
			pPointerToPointerOfPointers[i][x] = new int(rand());
		}
	}
	for (int p = 0; p < 10; ++p)
	{
		for (int q = 0; q < 10; ++q)
		{
			std::cout << "The value of at index " << q << " of the index " << p << " is " << *(pPointerToPointerOfPointers[p][q]) << std::endl;
		}
	}
	// deletion
	for (int r = 0; r < 10; ++r)
	{
		for (int s = 0; s < 10; ++s)
		{
			delete pPointerToPointerOfPointers[r][s];
		}
		delete [] pPointerToPointerOfPointers[r];
	}
                delete [] pPointerToPointerOfPointers;
	return 0;
}

That answers the question - using new and delete to accomplish this. (The question was not about std::vector - although, that is a viable solution to what he wants to do - but he asked for new/delete) It is best to answer how to do something, the way the person asks how to do it - that's what he asked for. In this case, it's a question of C++ logic - knowing the answer and understanding how it works will make a better programmer.