How to Call base Class Constructor

[Paul McKenzie]

Originally posted by Exceter
class X {
public:
X();
X(int);
} ;
class Y : public X {
public:
Y();
f() {//call X()};
G() {//call X(int)};
};

There is a reason why those functions are called constructors. What you are asking is impossible. How can you call the constructor if the derived class has already been constructed? Constructors are only called when constructing objects.

If you want to call a function in class X, make it a regular (non-constructor) function and call it from your Y class.

class X {
public:
    X() { DoXFunc(); }
    X(int n) { DoX2Func(n); }

protected:
    void DoXFunc() { }
    void DoX2Func(int n) { }
};

class Y : public X {
public:
   Y();
    void f() { DoXFunc(); }
    void G() { DoX2Func(1); }
};

And if from the Y constructor, you wanted to call a certain X constructor, you use something called a member-initialization list. But the bottom line is that you don't call constructors explictly, constructors are called automatically whenever you create an object.

Regards,

Paul McKenzie