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  1. #1066
    Join Date
    Aug 2001
    Location
    UK
    Posts
    48
    Kevin

    The way I came to the solution is to use a grid that I remember from puzzle books when I was a kid. Putting Y's where the crossing conditions were true and n's where they are not. I don't have all the steps (there were quite a few) but here is a pic of the full solution.
    Attached Images Attached Images

  2. #1067
    Join Date
    Sep 2002
    Location
    Philadelphia ***Epoch: Timeless***
    Posts
    560
    It's a bit misleading, the fish being highlighted in yellow, it makes it seem like it belongs to the owner of the yellow house when in fact that is not true. Also, the sheet is titled "results.xls". How am I to know what this is the result to? Is there more than one result, as indicated by the plurality of the title? This is possibly the most confusing document in modern human history. Please clarify.
    just kidding
    SolarFlare

    Those who cling to life die and those who defy death live. -Sun Tzu

    cout << endl;
    return 0;
    }

  3. #1068
    Join Date
    Aug 2001
    Location
    UK
    Posts
    48
    Solarflare

    It seems I have been revealed 'results' refered to attempt to use the grid to predict the 3.15 at Cheltenham as well as this little riddle. I was however unsuccessful, it seems Dirk Gently was wrong.

  4. #1069
    Join Date
    May 2001
    Posts
    112
    That's funny when I view the document it says Result.xls. I must be seeing a different document because a Super Moderator wouldn't make a mistake like that. More detective work is needed!

    -Ben

  5. #1070
    Join Date
    Sep 2002
    Location
    Philadelphia ***Epoch: Timeless***
    Posts
    560
    Originally posted by TimD
    It seems I have been revealed 'results' refered to attempt to use the grid to predict the 3.15 at Cheltenham as well as this little riddle. I was however unsuccessful, it seems Dirk Gently was wrong.
    That would be great if Mr. Gently and his holistic detective agency were real. But guess what.

    Originally posted by bmacri
    That's funny when I view the document it says Result.xls. I must be seeing a different document because a Super Moderator wouldn't make a mistake like that. More detective work is needed!
    Ah, yes. That seems to be because I didn't even look at the image. I looked at it in binary, and as such, it is easy to miss a single letter as my eyes zip past the 0s and 1s. But it appears TimD was using the grid to find multiple results, as confessed above, thus supporting my point irregardless.
    SolarFlare

    Those who cling to life die and those who defy death live. -Sun Tzu

    cout << endl;
    return 0;
    }

  6. #1071
    Join Date
    Nov 2002
    Location
    Sofia, Bulgaria
    Posts
    661
    there is only one result that fits all facts
    It's only when you look at an ant through a magnifying glass on a sunny day that you realise how often they burst into flames

  7. #1072
    Join Date
    Nov 2002
    Location
    Sofia, Bulgaria
    Posts
    661
    so a new one!!
    WOWOWOW!!!

    you have four digits that are the same for example 1,1,1 and... 1 (funny huh) try to get 4 using all mathematical operations you know but without using anu more digits. for example 1+1+1+1 = 4
    So do this for the other nine digits (0,2,3,4,5,6,7,8,9) Good luck!


    PS this is one dead thread
    It's only when you look at an ant through a magnifying glass on a sunny day that you realise how often they burst into flames

  8. #1073
    Join Date
    Nov 2002
    Location
    Foggy California
    Posts
    1,245
    An equation with zeros? How? .... Hmmm.... That will be the last one I will tackle. Any hints on that one?

    1+1+1+1 = 4 (already given)

    2*2/2*2 =4
    2*2/2+2 =4
    (2+2)/2*2 =4
    (2+2)/2+2 =4
    2+2+2-2 = 4
    (....)

    (44 mod 4) + 4 = 4

    (5 - 5/5) mod 5 = 4

    (66-6) & 6 = 4 [that is "(66-6) bitwise-and 6 = 4"]

    77/7 - 7 = 4

    That's all I can think of before my meeting. I'll have to ponder further 3, 8, 9, and 0.

    - Kevin

  9. #1074
    Join Date
    Nov 2001
    Location
    Beyond Juslibol
    Posts
    1,688
    0! + 0! + 0! + 0! = 4

  10. #1075
    Join Date
    Nov 2002
    Location
    Foggy California
    Posts
    1,245
    (3 | 3) + 3/3 = 4
    (3 & 3) + 3/3 = 4

  11. #1076
    Join Date
    Nov 2002
    Location
    Foggy California
    Posts
    1,245
    Bravo Dr Luz!

  12. #1077
    Join Date
    Nov 2001
    Location
    Beyond Juslibol
    Posts
    1,688
    (9/&radic;9)+9/9 =4

  13. #1078
    Join Date
    Nov 2001
    Location
    Beyond Juslibol
    Posts
    1,688
    And the last one corrected

    (8/3&radic;8)+8-8

  14. #1079
    Join Date
    Jan 2001
    Posts
    22
    What was the question?

  15. #1080
    Join Date
    Nov 2002
    Location
    Foggy California
    Posts
    1,245
    I don't know if the cube root counts b/c the digit '3' shows up in the equation. Seventh Star, does that count?

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