get more than one value from a function

[shitij]

Is there a way to get more than one value from a function. Presently function just return one value as specified in its return type.

[NigelQ]

You can pass in pointers or references to functions. These can be used to return information to the caller.

For example:

// some routine
{
         
         int FirstParam = 0;
         int SecondParam = 0;

         MultipleReturns(FirstParam, &SecondParam);

         printf("FirstParam = %d, SecondParam = %d\n", FirstParam, SecondParam);

}


// The function returning more than one thing
void MultipleReturns(int & First, int *Second)
{

         First = 21;
         *Second = 45;

}

You'll notice that FirstParam is passed by reference, and SecondParam is passed as a pointer.

Just for grins, I declared the routine void (no return value).

Hope this helps,

- Nigel

[shitij]

Thaknks for your advise. I am able to get the values as I wanted it to be.

[NMTop40]

You can also return 2 values by using std::pair< T1, T2 > where T1 and T2 are the types.

Any more and you can always put them into a struct and return the struct.

The other option, as been mentioned above, is for the function to take non-const references (or pointers) and write the values into there.

[Teddybare]

If there are a lot of variables let's say int

int MyArray[10];

you can send int* MyArray as an argument to the function and then access the whole array by reference.

Ted

[KevinHall]

Another option is to try boost::tuple.

[YourSurrogateGod]

Another option is to try boost::tuple.

What do you mean exactly? I've never heard of this.

[KevinHall]

Boost is a library of features that people hope will be added to the C++ standard. Actually, there's more to it than that, but I digress. So you can view boost as a free addon library.

Anyway, here is the documentation for boost::tuple.