Originally Posted by
iExtreme
I'm just stupid, but shouldn't it be a best match even with out the * ?
It's not a "best match" because it's not even a legal definition. The signature of a function template specialization must match the signature of the to be specialized function template.
So you can write
Code:
template <> char* maxn<char>(char* str[], int ct); // illegal, it's a potential specialization of a function template with signature template <class T> T* maxn(T* str[],int);
template <> char* maxn<char*>(char* str[], int ct); // ok, it's a specialization of a function template with signature template <class T> T maxn(T str[],int);
template <> char* maxn(char* str[], int ct); // ok, as above; but this time the type is deduced
char* maxn(char* str[], int ct); // ok, a function overload
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