3D array memory allocation dimensions

[monarch_dodra]

So like that?:

delete [] array3d[0][0]
delete [] array3d[0]
delete [] array3d

I hope, it's right now :-) There will be needed no for cycles?

Nope, you are still missing a ton of deletes. The syntax is;

delete [] pointer;

the keyword is "delete []", which will delete the array allocated at pointer. Note that at no point in time do you specify the size of the object to be deleted. You need one delete per allocation, so in your case:

for (int x = 0; x < HEIGHT; ++x)
{
    for (int y = 0; y < WIDTH; ++y)
    {
        delete [] test[x][y];;
    }
    delete [] test[x];
}
delete [] test;

Just delete in the oposite order that you allocated.

EDIT: Arrays are "fun" for learning, But I highly recommend you learn to use vectors. Understanding how an array works is important, but learning to use vectors correctly is even more important.